Segmentation table doubt

Segmentation table doubt

Postby testos » Mon Mar 07, 2011 1:31 am

Hi.

I attach screenshot for:
- Winning Number Table for a test Lotery.
- Summary History for previous table.
- Latest History for previous table.


In Latest History, How do you calculate the Sum differences: Min= -5 Max= 45?


Best Regards.
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Re: Segmentation table doubt

Postby stan » Mon Mar 07, 2011 12:15 pm

max = the_count_of_numbers_in_the_pool - 5 * the_lowest_difference = 50 - 5 * 1 = 45
min = the_count_of_numbers_in_the_pool - 5 * the_highest_difference = 50 - 5 * 11 = -5
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Re: Segmentation table doubt

Postby testos » Mon Mar 07, 2011 1:17 pm

Thank you for your reply.

What can be useful these values?
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Re: Segmentation table doubt

Postby stan » Mon Mar 07, 2011 1:47 pm

testos wrote:What can be useful these values?

it shows the maximum possible range of history differences for the next draw. if the maximum range is -5 to 45 as in the example above then it doesn't make any sense to estimate that the next history differences will be e.g. -15 to +5. a half of your estimated range would be wasted then (-15 to -4).
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Re: Segmentation table doubt

Postby testos » Mon Mar 07, 2011 3:10 pm

Okay, but previous algorithms don't work for the lottery (6/49) and level (4) attached. I must be doing something wrong :cry:

max = 49 - 6 * 1 = 43
min = 49 - 6 * 42 = -203
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Re: Segmentation table doubt

Postby stan » Mon Mar 07, 2011 3:20 pm

testos wrote:Okay, but previous algorithms don't work for the lottery (6/49) and level (4) attached. I must be doing something wrong

because there are only 3 numbers with the difference of 1
the formula in this case is: max = 49 - 3*1 - 3*2 = 40
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Re: Segmentation table doubt

Postby testos » Mon Mar 07, 2011 4:19 pm

Now I've understood.
In the same way for the Min:

min = 49-1*42-1*39-1*29-1*24-2*22 = -129

Thank you very much.
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