WNH Distinct Diff Counts

[laurontario]

Hello Stan,

Thanks for introducing the WNH distinct diff counts in the Statistics - it really helps.

I come up with another request: could you add one more table to that page with details for all draws?

Something like this:
DrawDate Col0 Col1 Col2 Col3 Col4 Col5 Col6 Col7 Col8 Col9 Col10
09.02.2008 6 5 5 5 4 6 6 3 5 6 5
06.02.2008 4 4 6 5 6 6 5 6 4 4 5
02.02.2008 4 5 5 5 6 6 5 4 6 5 6
30.01.2008 6 6 5 4 6 6 6 4 4 5 5
26.01.2008 6 6 5 6 5 6 6 6 6 5 6
23.01.2008 4 6 5 5 6 5 3 5 6 4 5
19.01.2008 6 6 5 3 6 5 4 6 5 6 5
16.01.2008 6 3 6 5 6 3 5 6 5 5 5
12.01.2008 6 5 4 5 5 3 5 6 6 5 4
09.01.2008 5 5 5 5 4 5 6 6 6 4 5
05.01.2008 5 6 4 5 5 6 6 6 5 6 6
02.01.2008 4 5 5 5 4 4 5 5 3 2 5
29.12.2007 5 6 6 6 6 5 6 4 6 6 6
26.12.2007 5 5 5 6 6 4 5 6 6 5 6
22.12.2007 5 5 4 5 4 5 5 5 6 5 5

I think that this could be useful.
I also think about creating a table showing the occurrences of multiple hits - see attached image.

This way we could predict, in case of multiple hits (see Col5 where we have 6 that hit 5 times in a row) whether is expected to have another hit or not. In this case we could eliminate that from our filter.

Example on the attached image (which, BTW, represents the number of drawn numbers that were also in the previous draw):
If there were no numbers drawn from the previous draw (L0 =0) and this is the 4th time in a row when it happens, chances are very slim for this to happen again in the next draw.

To calculatet his one should start from the oldes draw and count the number of repetitive occurences.
In my example above, for col0, 5 appeared 3 times in a row, then 4 was once, then we had 5 again twice, etc.
The 6 that appeared on the last draw won't be counted as we don't know yet what will follow in the next draw.
Same situation applies to Col5 where 6 hit 5 times in a row. For that column the count must stop at the Jan. 23 draw.

I am not sure if this is clear but, if not, please let me know and I could elaborate a bit more.

Could you, please, look into this and let me know?

Thanks,

Laurentiu

[CARBOB]

I think the Summary table shows each draw!!

[CARBOB]

The stats also show repeats.

[Jerzy]

Hello Stan and Laurontario,

I support Laurontario's idea and I would like to notice that on the basis of the WNH distinct diff counts several other filters can be created in addition to those which already exist.

For example, Total Distinct Differences Count (the sum of distinct differences in all columns) and Standard Deviation of Distinct Differences (in all 11 columns).

The distinct WNH differences can have the same Total Count value but they will have different standard deviation.

5, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5 Total Count = 54, Standard Deviation = 0,301511
4, 4, 6, 5, 5, 6, 5, 5, 5, 6, 3 Total Count = 54, Standard Deviation = 0,94388

Jerzy

[laurontario]

[quote=CARBOB]
I think the Summary table shows each draw!!
[/quote]

Damn it! They are in different places (WNH and Stats) that's why I couldn't find it.

Thanks, Carbob!

[Picsou]

Concerning this type of statégy for the different filter WNH diff count, I recommend you to read the posts of me even and of Tax to this subject.

Indeed the difficulty reside in the choice of the composition of the arrangement of 11 numbers.
It is necessary at first to determiner the good combination) of "3, 4, 5 and 6". how many?? 4^11 ?? if 3,4,5 and 6 used.

He has to exist there a lot, knowing that general there is more than "5", â€￾6â€￾ than that ""3 or 4".
Then, once this good chosen combination, it is necessary to choose the good arrangement.

For example if one chosen, 3* " 4 "; 4* " 5 ", and 4 " 6 ", there are 11550 possibles arrangements.
The study which I made on my loto, proves that same arrangements brought out 4 * 3 times, and several times twice, what is very little as recurrence. (more 4500 draws)

It is necessary to know , that the more the arrangement has ""5 and 6", the more the filter gives of tickets to play (Up to one thousand). So, in that case, it is necessary to choose one or several combinations complex (with several "3, 4", and few of "5 and 6", because it gives of one in 30 tickets to play.
You have to work out again tickets after every draw , keep always same arrangements.
In this methode, it is necessary to wait ...... it can be tres length....to win, but if it’s your arrangement, you must have jackpot.

See sheet excel, for some idea
(Thanks for traductor www.reverso.net)

Cordialement

[laurontario]

[quote=Picsou]
You have to work out again tickets after every draw , keep always same arrangements.
In this methode, it is necessary to wait ...... it can be tres length....to win, but if it’s your arrangement, you must have jackpot.

[/quote]

Hmmm... this is a different and interesting approach - don't chase the Jackpot, let the Jackpot come to you.

Thanks for sharing, Picsou.


Edit:
I think that would be a long wait.
I ran a report on my 649 for the last 200 draws to see which combination appeared the most. I noticed that 4-5-2-0-0 (that is, 4x6, 5x5, 2x4, 0x3, 0x2) appeared 134 times out of 2000 - this is only 6.7%. The next one is 5-5-1-0-0, which appeared 105 times (5.3%).
Only if we could create a report based on the number of occurences and see when was the last time when this appeared, is it 'due' soon, etc., otherwise I'm afraid this is not going to work very well.

Other thoughts?

[PadawanLotto]

I was wondering if anyone has found more than one occurrence of any one pattern? If so, how many?

[laurontario]

[quote=PadawanLotto]
I was wondering if anyone has found more than one occurrence of any one pattern? If so, how many?
[/quote]

You mean, for all 11 columns, like '6-6-5-6-4-5-5-6-6-5-6'?

I ran a report for the last 2000 draws and there were just a few repeats (that is, 2 occurrences), the rest was one only.

It's not something that one can use.

[laurontario]

[quote=laurontario]
Edit:
I think that would be a long wait.
I ran a report on my 649 for the last 200 draws to see which combination appeared the most. I noticed that 4-5-2-0-0 (that is, 4x6, 5x5, 2x4, 0x3, 0x2) appeared 134 times out of 2000 - this is only 6.7%. The next one is 5-5-1-0-0, which appeared 105 times (5.3%).
Only if we could create a report based on the number of occurences and see when was the last time when this appeared, is it 'due' soon, etc., otherwise I'm afraid this is not going to work very well.

Other thoughts?
[/quote]

This combination - 4-5-2-0-0 - appeared, as I said, 134 times, with a longest skip of 54 draws, a shortest of 0 and an average of 14.

Assuming that I filter my numbers with this combination (using the Occurrence of distinct H), and wait for the Jackpot, after filtering I still have 816,041 tickets left in the package and must find a way to bring it down to a playable size.

[PadawanLotto]

[quote=laurontario]
[quote=PadawanLotto]
I was wondering if anyone has found more than one occurrence of any one pattern? If so, how many?
[/quote]

You mean, for all 11 columns, like '6-6-5-6-4-5-5-6-6-5-6'?

I ran a report for the last 2000 draws and there were just a few repeats (that is, 2 occurrences), the rest was one only.

It's not something that one can use.
[/quote]

Yes, for all 11 columns. I have found one so far, looking at the last months worth of drawings I had one that repeated from 2005.

[CARBOB]

Padawan,

Out of 2410 draws I found 12 different combos that hit 3 times. Avg of around 200 draws for those. But one thing I noticed was all 12 of those combos were all 4's and 5's. I haven't backtest all of them, yet, but I am. The first Two I tested left 11 and 3 combos. None of the winning numbers were all 5's, so I would guess that combos made up of 4's and 5's would be safe, for Fla anyway. does anyway have any suggestions about how to best filter these. Here are the combos in case someone can use them.

[PadawanLotto]

[quote=CARBOB]
Padawan,

Out of 2410 draws I found 12 different combos that hit 3 times. Avg of around 200 draws for those. But one thing I noticed was all 12 of those combos were all 4's and 5's. I haven't backtest all of them, yet, but I am. The first Two I tested left 11 and 3 combos. None of the winning numbers were all 5's, so I would guess that combos made up of 4's and 5's would be safe, for Fla anyway. does anyway have any suggestions about how to best filter these. Here are the combos in case someone can use them.
[/quote]

I had no drawings with all 4's or 5's. The 1's and 2's are rare so I filter them out altogether. The 3's best range for me is Columns -1 thru -10 Count min 0, max 1. The 4's and 5's best range all columns count min 3 to max 8. With the 4's and 5's I check all columns and the 4's and 5's then set the count.

[CARBOB]

[quote=PadawanLotto]
[quote=CARBOB]
Padawan,

Out of 2410 draws I found 12 different combos that hit 3 times. Avg of around 200 draws for those. But one thing I noticed was all 12 of those combos were all 4's and 5's. I haven't backtest all of them, yet, but I am. The first Two I tested left 11 and 3 combos. None of the winning numbers were all 5's, so I would guess that combos made up of 4's and 5's would be safe, for Fla anyway. does anyway have any suggestions about how to best filter these. Here are the combos in case someone can use them.
[/quote]

I had no drawings with all 4's or 5's. The 1's and 2's are rare so I filter them out altogether. The 3's best range for me is Columns -1 thru -10 Count min 0, max 1. The 4's and 5's best range all columns count min 3 to max 8. With the 4's and 5's I check all columns and the 4's and 5's then set the count.
[/quote]

I would be willing to bet, there are not many combinations of Distinct Occurancea that leave 10 or less combos to play. I think Tag's idea of someway to filter out all the combinations that leave over a set number, the Jackpot will be there!!

[CARBOB]

[quote=CARBOB]
[quote=PadawanLotto]
[quote=CARBOB]
Padawan,

Out of 2410 draws I found 12 different combos that hit 3 times. Avg of around 200 draws for those. But one thing I noticed was all 12 of those combos were all 4's and 5's. I haven't backtest all of them, yet, but I am. The first Two I tested left 11 and 3 combos. None of the winning numbers were all 5's, so I would guess that combos made up of 4's and 5's would be safe, for Fla anyway. does anyway have any suggestions about how to best filter these. Here are the combos in case someone can use them.
[/quote]

I had no drawings with all 4's or 5's. The 1's and 2's are rare so I filter them out altogether. The 3's best range for me is Columns -1 thru -10 Count min 0, max 1. The 4's and 5's best range all columns count min 3 to max 8. With the 4's and 5's I check all columns and the 4's and 5's then set the count.
[/quote]

I would be willing to bet, there are not many combinations of Distinct Occurancea that leave 10 or less combos to play. I think Tag's idea of someway to filter out all the combinations that leave over a set number, the Jackpot will be there!!
[/quote]

I would love to be able to import the entire 5/36 package with the Distinct Occurances and test my theory, but we don't have that ability, yet.