Numbers Order in Column

Postby CARBOB » Tue Oct 27, 2009 6:29 pm

[quote=Lexus]
[quote=Jerzy]
Lexus,

Sorry I am unable to use Russian fonts.

Eto ochen interiesnaia idea, no k sazhalieniu ia ponimaiu nie vsio. Izvinitie. Pishitie po Russki.
[/quote]

In an explanatory investment to tables, and possibility of their use on examples.
The text in Russian.
I can translate into English to whom it is interesting
[/quote]

That would be very generous on your part and much appreciated. Thank you.
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Postby Lexus » Tue Oct 27, 2009 8:17 pm

Translate in English
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Postby CARBOB » Tue Oct 27, 2009 10:37 pm

[quote=Lexus]
Translate in English
[/quote]

Lexus, thank you for the translation and explanation. A lot of work for you, that's very much appreciated.
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Postby Jerzy » Wed Oct 28, 2009 4:56 am

Lexus,

Thank you for presenting to us your ideas.

I will read and analyze your presentation in detail. The Russian version seems to be more understandable than the English one. I understand Russian quite well but it is much easier for me to write in English.

At first glance your ideas seem very complex. Because there are many theoretical and practical consideration, probably I need several days to think about it and to discuss my findings on the Forum.
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Postby Joe » Wed Oct 28, 2009 5:25 am

[quote=lottoboy:1256535052]
[quote=Joe:1255514815]
[quote=lottoboy:1255228285]
Hi, Joe:

Could you create or repaire the Filter of Number Order in Col. for Pick-5
ASAP now instead of waiting EL5 if possible? Thanks.

Best,
lb
[/quote]

yes i do, may be this week-end
[/quote]

Hi, Joe:

How about your Filter of Number Order in Col. for Pick-5 now?
[/quote]

yes doing, sorry for the delay, i try to finish this week-end, thanks
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Postby Lexus » Wed Oct 28, 2009 9:17 am

Greetings to all!

1. If transfer (the sense of idea is more true) is not clear, I can describe in more details interrelation of the theory and practice or any not clear moments which is difficult for understanding.

2. And also who can prompt?

The lottery 6 of 52 gives 20 358 520 combinations
The lottery 5 of 42 gives 850668 combinations

How many combinations will be if?

11 columns
We use 1/3 columns, that is 240 of 720 possible shifts

11 from 33. Correctly?
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Postby Lexus » Wed Oct 28, 2009 11:36 am

Hi Joe!

I can assume that you are now very occupied.
But you could give a little your time for consideration of my offers.

For check of my theory a lot of time, and also attentiveness is necessary at data input in your filter.
If you read my previous Post could pay attention that for check of 63 variants on 4 columns I needed 6 hours.
And it is final 200 or even 300 variants on 11 columns I are simple not in forces to test, and very much it would be desirable to learn, what results will be.

As the way offered by me is based on association of results, performance probably in parallel on two, three etc. computers. I have an access to two powerful enough computers.

That it to make it is necessary to make changes to your filter. Namely:

1. Your filter works by a principle 1 result for 1 pass:
a. We choose a column or columns
b. We mark necessary positions and the data for filtering
c. We mark "Position Count" and "Column Count"
d. We choose Remove or Leave
e. OK

2. I offer principle Ð￾ of results for 1 pass:
a. We choose only one of columns
b. We open a file.scv.txt in which there are shifts for filtering
1,2,3,4,5,6
2,5,6,4,3,1
4,2,5,3,1,6
Etc.
c. We choose a file where to keep the received (INCORPORATED) results.
d. We choose Remove or Leave
e. OK

Thus we receive total result, only after the program will calculate all variants which we will specify it in an entrance file
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Similarity with Multi-Segment File Filter

Postby Midas » Thu Oct 29, 2009 3:01 pm

Greetings Gentlemen,

Thank you all for your excellent ideas!.

Stan/Joe/Lexus/Teoman can you give us your opinion on the following. Thanks.

The more I think about this plugin, I feel we need statistics to properly select the proper combination from the WNH segment (s0 to s10).
The problem I'm having is getting a handle on what to select for each column and position before applying the min/max settings.

I'm sure there are ways to summarize the statistics per position which could be presented as a generic statistics page in EL.

For more detailed statistics, I was wondering if the statistics page could be calculated for each combination then exported into a file for external viewing/processing,
like the existing multi-segment file output.

I notice these excellent filters are extremely powerful and we need to think how we can marry up new statistics with existing plugin filter output.
In other words amending the output of the excellent multi-segment file results to include the Number Order in Column statistics as additional output?.

Looking at your word document, you present a winnings data for the various winning combinations. This can be viewed back in the winning tab in the EL main application.
Lexus were you thinking of having a combination along with its winning hit rate shown in the table?.

Good luck to everybody and Keep Up the great work. :anx:

Cheerz
Midas
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Postby teoman » Thu Oct 29, 2009 3:44 pm

Greetings to all!

The 720 combinations is found at: http://www.expertlotto.com/en/forum/for ... age=4#9978

Regards,
TM.
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Postby Lexus » Thu Oct 29, 2009 6:24 pm

[quote=teoman]
Greetings to all!

The 720 combinations is found at: http://www.expertlotto.com/en/forum/for ... age=4#9978

Regards,
TM.
[/quote]

Combinations of shifts are calculated there not truly. Somewhere about 16-20 errors.
Example:
1,4,3,5,3,6 2,4,3,5,1,6 3,4,2,5,1,6 4,3,2,5,1,6 5,3,2,4,1,6 6,3,2,4,1,5
1,4,3,5,6,3 2,4,3,5,6,1 3,4,2,5,6,1 4,3,2,5,6,1 5,3,2,4,6,1 6,3,2,4,5,1
1,4,3,6,3,5 2,4,3,6,1,5 3,4,2,6,1,5 4,3,2,6,1,5 5,3,2,6,1,4 6,3,2,5,1,4
1,4,3,6,5,3 2,4,3,6,5,1 3,4,2,6,5,1 4,3,2,6,5,1 5,3,2,6,4,1 6,3,2,5,4,1

Correct calculation in the attached file
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Postby teoman » Thu Oct 29, 2009 7:47 pm

Greetings to all!

Sorry, but we corrected the 10 errors. Thanks.

Regards,
TM.
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Postby Jerzy » Fri Oct 30, 2009 3:05 am

Lexus,

How many combinations will be if?

11 columns
We use 1/3 columns, that is 240 of 720 possible shifts




There will be 240 number order patterns in each of 11 columns that we want to use.

The total number of combinations:

240*240*240*240*240*240*240*240*240*240*240 = 1.521681143^26
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Postby Jerzy » Fri Oct 30, 2009 5:30 am

Lexus,

I understand that you want to build a new version of the Numbers Order in Column filter. Your filter would work with only one column at a time, and it would use not one but many patterns or variants of number order in columns . The number order variants would be included in a separate .csv or .txt file. The filter would work with any number order variants that would be entered by the user. 720 such variants are possible for 6/xx lottery. The tickets remaining after the filtering would be collected in a special file, and separated from the general package at the final stage. Leave or Remove options should be available.

Probably your filter would be more powerful than the existing Numbers Order in Column filter.

You give us examples to show how it could work. If we use 8 variants in 4 columns, there will be 4096 combinations (8*8*8*8 = 4096). Probably too many combinations. As a way around the problem you suggest adding the variants 8+8+8+8 = 32

32 is much less than 4096 and, in my opinion, it could be just not enough to get the right tickets in the package.

Actually, I cannot check you calculations in your Excel spreadsheet, because you calculated everything outside of Excel and just entered the result of caculations manually. But I believe you.

I do not know what you mean by uniting the results. What's that? Why do you do it? How do you do it? Did you try to use the Joe's filter for testing your ideas or a different piece of software?

Prefiltering the package with different filters to get approximately 1,000,000 tickets before using the new filter, as you propose, would decrease the time of filtering.

In point 3 of your remarks you suggest that it is possible to remove the majority of tickets from the package by using 650 - 700 number order variants. But it is important to know how many columns can be used or should be used with so many number order variants to achieve acceptable results. Probably we do not know that yet.

You mentioned quite rightly that there should be no correct number order variant at least in one of the columns to keep the jackpot ticket in the package. But you did not mentioned clearly that the filter should be set for Remove option.

The same result can be achieved if we use 20 - 70 number order variants, with the correct variant present, for the same columns, and with the filter setting Leave. Probably the processing time would be the same as for Remove option, unless different algorithms are used, but finding 20 - 70 number order patterns to leave seems to be easier than finding 650 - 700 to remove.

How this filter can be implemented, only the programmers could tell. I hope that your filter idea will attract Stan's and Joe's attention.

Best Regards

Jerzy
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Postby stan » Fri Oct 30, 2009 11:54 am

[quote=Jerzy]
How this filter can be implemented, only the programmers could tell. I hope that your filter idea will attract Stan's and Joe's attention.
[/quote]

it will have to wait until the core infrastructure is finished...
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Postby Lexus » Fri Oct 30, 2009 1:49 pm

[quote=Jerzy]
Lexus,

How many combinations will be if?

11 columns
We use 1/3 columns, that is 240 of 720 possible shifts




There will be 240 number order patterns in each of 11 columns that we want to use.

The total number of combinations:

240*240*240*240*240*240*240*240*240*240*240 = 1.521681143^26
[/quote]

Precisely!

But, If to use a method of connection of results 240 variants *11=2640 turn out, or 75 variants *11=825 (it is important! At 75 variants win a combination, it agree calculations, will be already in-5--6 to a column, therefore to use columns more-7 - a high probability of loss WIN Numbers)

For example the principle of connection of results is used in Winning Numbers History filtre!
We choose an interval from-n to +n for each column, instead of individual value n for one pass.

Thus, if to use a principle which is used in Winning Numbers History filtre we will have an interval from n to n (from 0 to 45 (46), from 100 to 287 (188), from 560 to 720 (61) etc.)
And it in turn, will limit us in a choice
I hope, at me it has turned out to explain
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