teoman wrote:03, 06, 21, 25, 38, 16 => 2+1+0+1+2
02, 11, 15, 26, 40, 16
all six numbers are adjacent to the previous draw in this case. and your filter settings specify that at most two adjacent numbers are allowed in a matching ticket.
teoman wrote:03, 06, 21, 25, 38, 16 => 2+1+0+1+2
02, 11, 15, 26, 40, 16
stan wrote:so there would be a series of transformations changing each pool number into one or more other numbers and the filter would accept tickets that have 0 to 6 transformed numbers (in a 6/xx lottery), right?
stan wrote:so there would be a series of transformations changing each pool number into one or more other numbers and the filter would accept tickets that have 0 to 6 transformed numbers (in a 6/xx lottery), right?
stan wrote:teoman wrote:03, 06, 21, 25, 38, 16 => 2+1+0+1+2
02, 11, 15, 26, 40, 16
all six numbers are adjacent to the previous draw in this case. and your filter settings specify that at most two adjacent numbers are allowed in a matching ticket.
teoman wrote:07, 08, 15, 26, 39, 40 => 2+2+2+2+2
03, 05, 06, 09, 34, 36
Gatsby wrote:, or any other move as a matter of fact, that´s all permutations.
stan wrote:teoman wrote:07, 08, 15, 26, 39, 40 => 2+2+2+2+2
03, 05, 06, 09, 34, 36
there are four adjacent numbers in this case (7,8,39,40) so the the ticket is failing the condition that at most 2 adjacent numbers are allowed
(btw, don't know what your 2+2+2+2+2 means)
teoman wrote:stan wrote:teoman wrote:07, 08, 15, 26, 39, 40 => 2+2+2+2+2
03, 05, 06, 09, 34, 36
there are four adjacent numbers in this case (7,8,39,40) so the the ticket is failing the condition that at most 2 adjacent numbers are allowed
(btw, don't know what your 2+2+2+2+2 means)
Give another example, without consecutive double:
04, 15, 18, 24, 31, 35 => 2+1+2+2+2
01, 12, 19, 23, 29, 35
2+1+2+2+2 means:
+/-1 => 2 => (18, 24)
+/-2 => 1 => (31)
+/-3 => 2 => (04, 15)
+/-4 => 2 => (15, 31)
+/-5 => 2 => (18,24)
or
[+/-1 => 2 => (18, 24)]+[+/-2 => 1 => (31)]+[+/-3 => 2 => (04, 15)]+[+/-4 => 2 => (15, 31)]+[+/-5 => 2 => (18,24)].
Gatsby wrote:Sure,
Same numbers from previous draws: 1 "permutes" with 1; 2 permutes with 2, ... 50 permutes with 50
Adjacents A (+1): 1 permutes with 2, ..., 49 permutes with 50, 50 permutes with 1
Adjacents b (-1):2 permutes with 1, ...., 50 permutes with 49
Permutations by 2: 1 permutes with 3, 2 permutes with 4,...., 47 permutes with 50, 48 permutes with 1, ...
Permutations by 3: 1 permutes with 4, 2 permutes with 5, ...., 46 permutes with 50, ...
Permutations by 4:
... etc...
Permution with odds: 1 permutes with 3, 3 permutes with 5, 5 permutes with 7, etc, (and all the evens are maintained)
Permutation with evens: 2 permutes with 4, 4 permutes with 6, etc (all odds are mantained)
etc (i think you see the logic).
I know it may seem strange but generally in most cases the combinations originated by this transformations (from the last draw combination) do not carry more than 3 numbers to the next draw. In a 50 set number there are many different ways to do permutations, adjacents, plus 2,3,4, ... till 25 (1 permutes with 25, 2 permutes 26, ...), are the most obvious permutations, others can be envisaged, and originate a set of combinations from wich we can saffely reduce the package, permuting ones and keeping others equal
As you understand these are all complete circular patterns (in the sense that you permute all or some numbers from 1 to 50, if you choose to let some stay equal), but it´s also possible that you can permute some
sub-groups, like 1 to 10, 11 to 20, and permute only within this subsets. Once you start considering it, it really makes sense because lottery isn´t predictable, and this way we are aiming at some repetitive comportment, which is not expectable. I can´t say if it will remove many tickets from package, but i can assure that for each permutation normally no more than 3 (usually 2) numbers come in the next draw. So we want to keep withdraw from the package combinations that have 5, 4, 3 or 2 numbers equal from each of this transformed combinations of 5 numbers.
Best Regards,
F.
stan wrote:you probably misunderstood how min/max option works. it specifies the 'total' minimum and maximum count of numbers with any adjacent distance. not the min/max of a single selected distance.
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