Arithmetic Complexity

[PadawanLotto]

Now I know everybody wants to hit the jackpot but, think about this, Arithmetic Complexity. Now I'm working with a 5/39 so your results may be different than mine.

If I filter Arithmetic Complexity at 3 it leaves 21,116 combinations and looking at the package check winnings over the past drawings I find that 2nd prize has 2 or more hits within those 21,116 combinations and well over 100 3rd prize hits.

If I filter Arithmetic Complexity at 4 I have 129,388 combinations and 29 or more 2nd prizes and well over 1,000 3rd prize hits.

Now the thing is how do I capture 1 or more of those 2nd prize hits and some of the 3rd prize hits?

Arithmetic Complexity is a non-draw based filter meaning that no matter what the last drawn numbers were if you filter it for a 3 it will always produce the same 21,116 combinations.

[kdsjeter]

Padawan,

Actually with 5/39 you can reduce the 575757 down to 9177 using the reduce, optimize coverage, 4 of 5.

The resultant package which I call a quad base has a guarantee of at least 1, 4 of 5 hit every draw.
I have experimented with Arithmetic Complexity and find that the setting of 6 comes out the
most and reduces the overall package by about 50%. Of course the guarantee goes away when
you do that.

I have attached the quad base package. It applies to any 5 of 39 lottery.

[kdsjeter]

Went back and applied Arithmetic Complexity filter to my 9177 quad base with a setting of 6 and got 4338 combinations.

Back tested for the last 40 days and 33 out of 40 days had 1 or more 4 of 5 ($400 Winners). There were a lot of 2 and 3 $400 hits as well.\

So I thought applying the filter would yield about 50% or 20 days with hits. Turns out for this test it was 82.5%. That is pretty stellar
since I am now close to the overall odds of having a 4/5 hit (1 in 3489).

So I will now be using the 4338 as my quad modified base. Eventually I might hit this thing.

[PadawanLotto]

Nice, and we still can't capture a 2nd or multiple 3rd prize wins or play for a profit.

[kdsjeter]

Yeah ... the house always wins is still true. We are still left to tinker, back test, re-adjust.

Has anyone won yet using EL?

[royon]

Hi,
That's a good question. All I can say is that the software is very useful.
When I was a trial licence user, I tested all kind of strategies. I've played once with real money during the trial period. I've remained at that time with 1/20 of the full wheel and there was the jackpot ticket there. I didn't hit the jackpot but with 17 tickets played (best tickets), I got back 85% of the money .
Testing with a more difficult game, I've remained with 1/100 of the full wheel with the jackpot ticket there. Playing all the tickets would cost me $500k and the profit would be of $3.8 million for that draw. Now, how to play all the remaining combos? You must have a very rich and optimistic investor, also time to register all the tickets .

[Da80th]

I just notice AC from EL compare to AC from another lotto software show different values. In EL, AC show 0 and 1, and other software show 2 and 3 for the same date...this is for pick 3 game.


please see attached image.

Da80th

[Da80th]

I found a tweak that can improve this AC filter, how about analyze AC values for last digit and filter it.

See below how different AC values for last digit compare to regular lotto numbers, this is for California Fantasy Five game 5/39

Last Digit Arithmetic Complexity
1-Jan-13 2
2-Jan-13 1
3-Jan-13 2
4-Jan-13 0
5-Jan-13 3
6-Jan-13 2
7-Jan-13 1
8-Jan-13 1
9-Jan-13 3
10-Jan-13 1


Regular lotto numbers
1-Jan-13 6
2-Jan-13 6
3-Jan-13 4
4-Jan-13 5
5-Jan-13 5
6-Jan-13 5
7-Jan-13 6
8-Jan-13 4
9-Jan-13 6
10-Jan-13 6

As you can see same lotto draw results with different AC values, so now we can filter out the last digit as well as normal draws.

Da80th

[PadawanLotto]

I just notice AC from EL compare to AC from another lotto software show different values. In EL, AC show 0 and 1, and other software show 2 and 3 for the same date...this is for pick 3 game.

Da80th

Based on the formula found in the link 0 and 1 should be correct, I don't know how the other software is calculating AC.
http://www.expertlotto.com/en/help/en/stats/ac.html