Unbelievable ... how to hit a jackpot.

Unbelievable ... how to hit a jackpot.

Postby edymurph » Thu Jun 13, 2019 6:57 pm

I'm opening this topic for lottery lovers and for those who like calculations.
In my recent studies, I have found that is it possible to find a pattern in these calculations, I can turn it into an application for any lottery mode.
I'll leave it here for those scholars and onlookers who want to try to find a pattern in these calculations.
If it has any pattern, the jackpot is in the hand, but if you find the calculations by approximation also works.
The only answers to (Position E) are available to see if all are on the right track, because here what matters is how to assemble the equation to reach these values.

LET'S SUPPORT THE FOLLOWING SCENARIO, WHERE WE HAVE 1640 ORANGES AND WILL DIVIDE THEM IN 11 PARTS, WHERE EACH POSITION WILL RECEIVE A VALUE ACCORDING TO ITS SPECIFICATION.
A (POSITION E) ALREADY HAS 865.276 ORANGES AND WE WANT TO KNOW WITH HOW MANY ORANGES IT WILL BE AT THE END OF THAT DIVISION.

(1) POSITION A = YOU CAN ONLY RECEIVE FROM (0-18) RECEIVED = 6
(2) POSITION B = YOU CAN ONLY RECEIVE FROM (22-82) RECEIVED = 46
(3) POSITION C = YOU CAN ONLY RECEIVE FROM (218-366) RECEIVED = 302
(4) POSITION D = YOU CAN ONLY RECEIVE FROM (672-892) RECEIVED = 782
(5) POSITION E = YOU CAN ONLY RECEIVE FROM (952-1176) RECEIVED = 1052
(6) POSITION F = YOU CAN ONLY RECEIVE FROM (644-880) RECEIVED = 744
(7) POSITION G = YOU CAN ONLY RECEIVE FROM (216-366) RECEIVED = 268
(8) POSITION H = YOU CAN ONLY RECEIVE FROM (24-94) RECEIVED = 70
(9) POSITION I = YOU CAN ONLY RECEIVE FROM (0-20) RECEIVED = 4
(10) POSITION J = YOU CAN ONLY RECEIVE FROM (0-4) RECEIVED = 2
(11) POSITION K = YOU CAN ONLY RECEIVE 2 AND ALWAYS RECEIVE = 2
SUM OF ALL NUMBERS = 3278
THEN WE WILL DIVIDIREMOS THE 1641 AND ALSO THE 1642 .... AND SO DURING UNTIL 1650.
HOW MANY ORANGES TO (POSITION E) WILL YOU RECEIVE AT THE END OF EACH DIVISION?

POSITION A 3,003= 0,091870%
POSITION B 50,050= 1,531162%
POSITION C 289,575= 8,858864%
POSITION D 772,200= 23,623637%
POSITION E 1,051,050=32,154,395%
POSITION F 756,756= 23,151164%
POSITION G 286,650= 8,769380%
POSITION H 54,600= 1,670358%
POSITION I 4,725= 0,144550%
POSITION J 150= 0,004589%
POSITION K 1= 0,000031%
TOTAL 3.268.760

(ANSWERS ONLY FOR POSITION E)
1640 = 866.362 (1086)
1641 = 867,438 (1076)
1642 = 868,502 (1064)
1643 = 869,612 (1110)
1644 = 870,598 (986)
1645 = 871,624 (1026)
1646 = 872,692 (1068)
1647 = 873,768 (1078)
1648 = 874,848 (1080)
1649 = 875,904 (1056)
1650 = 876,934 (1030)


What should be done here is as follows.
We have to make calculations to see how we get to these values ​​(866.362 .... 867.438 .... 868.502) and so on.
Note that the first 3 digits go up one by one, the problem is the final 3.

Let's suppose...
Taking the number 1640 and raising it to the square, it will be (2,689,600) multiplied by 32,154395% we obtain the value of
864,824 .... well near the value 866.362.
A difference of 1538.
I still do not know how to get the correct value, but I want to get closer, because this difference of 1538 is still great.
You do not need to find the values ​​for each number (5,6,7,8,9,10,11 13,13 14) because I only need one, and then I make that into something that I can apply in any lottery mode.
Last edited by edymurph on Fri Jun 14, 2019 5:29 pm, edited 2 times in total.
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Re: Unbelievable ... how to hit a jackpot.

Postby tintan » Fri Jun 14, 2019 2:11 am

Thumbs up for such an application !!!
:D :D :D tintan
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Re: Unbelievable ... how to hit a jackpot.

Postby D1Magnet » Mon Jun 17, 2019 6:20 pm

Hi edymurph, thank you very much for your post above. Could you please give an example of applying this idea to the Expert Lotto Demo 6/49 lottery to try and understand the idea better.
Thanks
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Re: Unbelievable ... how to hit a jackpot.

Postby edymurph » Mon Jun 17, 2019 6:43 pm

D1Magnet wrote:Hi edymurph, thank you very much for your post above. Could you please give an example of applying this idea to the Expert Lotto Demo 6/49 lottery to try and understand the idea better.
Thanks


put here in txt format all the results of your updated lottery to see what I can do.
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Re: Unbelievable ... how to hit a jackpot.

Postby D1Magnet » Tue Jun 18, 2019 1:45 pm

Hi edymurph, attached are the results of the Expert Lotto Demo 6/49 lottery that is available under Expert Lotto's available lotteries. I've made one file just the 6 main numbers out of 49, the other file has the bonus ball included also. The data goes back 962 draws. Thanks
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Re: Unbelievable ... how to hit a jackpot.

Postby edymurph » Tue Jun 18, 2019 5:05 pm

D1Magnet wrote:Hi edymurph, attached are the results of the Expert Lotto Demo 6/49 lottery that is available under Expert Lotto's available lotteries. I've made one file just the 6 main numbers out of 49, the other file has the bonus ball included also. The data goes back 962 draws. Thanks


See if it's this lottery.
Well, here are more than five thousand draws, why?
And your txt file starts in 2006 and runs through 2010.




Already understood
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Re: Unbelievable ... how to hit a jackpot.

Postby edymurph » Tue Jun 18, 2019 6:01 pm

D1Magnet wrote:Hi edymurph, attached are the results of the Expert Lotto Demo 6/49 lottery that is available under Expert Lotto's available lotteries. I've made one file just the 6 main numbers out of 49, the other file has the bonus ball included also. The data goes back 962 draws. Thanks


Here it is ... D1Magnet,
The file with the sum of the repeated numbers.
If here in EL had the range in the filter repeating numbers, you would put those values ​​here. (without bonus)
6 = 1
5 = 0
4 = 0
3 = 19
2 = 122
1 = 378
0 = 440
Now with the bonus
7 = 1
6 = 0
5 = 0
4 = 4
3 = 52
2 = 173
1 = 424
0 = 306
See I made these Statistics of the competition 1 through 960, okay?

You can verify this by using the filter by repeating numbers and choosing the last draw (960) and set the filter min and max in (zero) and you will see the number 440 in 6 numbers... and 306 in 7 numbers.

Now ... to use this to your advantage, just ask Stan to build that range inside the filter by repeating numbers, otherwise that's no use.
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Re: Unbelievable ... how to hit a jackpot.

Postby mimie » Wed Jun 19, 2019 4:18 pm

quick question how are u finding the sum of the repeating numbers in all the levels.
thanks
I would like to know more about this filter if u don't mind doing a step by step
thanks
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Re: Unbelievable ... how to hit a jackpot.

Postby edymurph » Wed Jun 19, 2019 4:33 pm

mimie wrote:quick question how are u finding the sum of the repeating numbers in all the levels.
thanks
I would like to know more about this filter if u don't mind doing a step by step
thanks


Friend...
I have software that shows me the sums of numbers passed based on (repeated numbers) for any mode.
But as I said before and I say again ...
To use this kind of information, the EL filter (repeating numbers) should have the range where I could put those values.
This was the first thing I looked for in this software as soon as I saw it, but unfortunately it has not.
I also say that with this filter if you hit the 3 numbers of your lottery within the range you reduce it by about 98%.
But I can not ask you to build this range to our friend Stan, because I only have the free version of EL, so I can not ask for anything.
now you who have the version paid, want to ask, feel free.
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Re: Unbelievable ... how to hit a jackpot.

Postby edymurph » Wed Jun 19, 2019 6:10 pm

Look that...
If the Expert Lotto had this range inside the filter (repeating numbers) ... we'll put it like this if we were to play for the 960 contest.

Last draws = 1 to 959
Min and Max (0-6) = 0
Range min and max = 440

After filtering with the 440, we will use the 378 with min and max in (1) and then the 122 with min and max in (2).
Only those 3 numbers ...
If you had this filter, you could see how much it would reduce using your entire lottery package
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Re: Unbelievable ... how to hit a jackpot.

Postby D1Magnet » Wed Jun 19, 2019 6:24 pm

Hi edymurph, thank you very much for calculating the statistics on the demo lotto. To get all 960 draws (in your attached text file) did you have to do them one by one and then paste into an excel sheet or text file? If so that would have took a lot of work.

With the statistics you wrote for draw 959 which is 2010/28 sun 1st , yours were 0=440, 1=378 for 6 numbers and 0=306, 1= 424 for 7 numbers.

When I did mine on draw 959 on the date above, I went to winning numbers, analyze, selected all 959 draws and selected the repeating numbers statistic. This was based on the 6 main numbers in the winning numbers history including the bonus ball.

My statistics came out with 0-6 (see attached screenshots) not 0-7 with a bonus ball

I got 0=386, 1= 421, 2=132 etc

Could you explain how you got these numbers on that draw of 959?

I also looked at your idea of creating a complex filter on the repeating numbers filter (as mentioned on your other post), but as you may already know, it doesn’t allow you to input a range eg 440 to 440 at level 0 etc, from within the complex filter.

Also when reducing the lottery package of 960 draws, these 960 draws (from your screenshot) must be the previously drawn 960 winning numbers, not the full package of 13.9 million

Thanks
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Re: Unbelievable ... how to hit a jackpot.

Postby edymurph » Wed Jun 19, 2019 6:41 pm

D1Magnet wrote:Hi edymurph, thank you very much for calculating the statistics on the demo lotto. To get all 960 draws (in your attached text file) did you have to do them one by one and then paste into an excel sheet or text file? If so that would have took a lot of work.

With the statistics you wrote for draw 959 which is 2010/28 sun 1st , yours were 0=440, 1=378 for 6 numbers and 0=306, 1= 424 for 7 numbers.

When I did mine on draw 959 on the date above, I went to winning numbers, analyze, selected all 959 draws and selected the repeating numbers statistic. This was based on the 6 main numbers in the winning numbers history including the bonus ball.

My statistics came out with 0-6 (see attached screenshots) not 0-7 with a bonus ball

I got 0=386, 1= 421, 2=132 etc

Could you explain how you got these numbers on that draw of 959?

I also looked at your idea of creating a complex filter on the repeating numbers filter (as mentioned on your other post), but as you may already know, it doesn’t allow you to input a range eg 440 to 440 at level 0 etc, from within the complex filter.

Also when reducing the lottery package of 960 draws, these 960 draws (from your screenshot) must be the previously drawn 960 winning numbers, not the full package of 13.9 million

Thanks


You saw the package with 960 down there because I left it there, because I was calculating the repeated values.
But that does not have anything to do with it, you're going to do this filtering with the 13 million combinations of your lottery.
Now ... from contest 1 to 959.
This is how the filter works, in case you know that in contest 960 came 440 to zero, because you already have the contest.
But if contest 960 did not happen, you would have to choose from 1 to 959, wagering on (0) of 440 of contest 960.
If you do 1 to 959 the way you did it will go wrong anyway.

I find that it gives to put min and max inside the filter estimates?
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Re: Unbelievable ... how to hit a jackpot.

Postby D1Magnet » Thu Jun 20, 2019 3:34 pm

Hi edymurph I exported the 960 draws from the winning numbers table into a csv file. I then loaded this into the package. From there I clicked: package, analyze, all 960 draws, repeating numbers and got the same results as you. Eg 0=440, 1= 378, 2=122, 3=19 etc

So the calculations I made above on draw 959 wouldn’t have been accurate, (as you said), as they were analyzed off the winning numbers table (not the package) and were for draw 959 not 960.


My apologies, I read your post above about using software to calculate all these statistics in the text files your posted.

edymurph wrote:I have software that shows me the sums of numbers passed based on (repeated numbers) for any mode.


What is the name of the software that would allow you to calculate the sums of numbers?

From what I see inside Expert Lotto, you’d have to calculate them one by one each game, without an additional software program that automates this calculation.

Regarding a registered user’s request for adding a min/max range value to the existing repeating numbers filter, I’d be happy to but first I’d like to know with the min/max ranges you type in: how come they would reduce a 13.9 million package (on the Demo 6/49 lotto) by such a large amount, by only using 3 levels as ranges?

Thanks
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Re: Unbelievable ... how to hit a jackpot.

Postby edymurph » Thu Jun 20, 2019 11:47 pm

D1Magnet wrote:Hi edymurph I exported the 960 draws from the winning numbers table into a csv file. I then loaded this into the package. From there I clicked: package, analyze, all 960 draws, repeating numbers and got the same results as you. Eg 0=440, 1= 378, 2=122, 3=19 etc

So the calculations I made above on draw 959 wouldn’t have been accurate, (as you said), as they were analyzed off the winning numbers table (not the package) and were for draw 959 not 960.


My apologies, I read your post above about using software to calculate all these statistics in the text files your posted.

edymurph wrote:I have software that shows me the sums of numbers passed based on (repeated numbers) for any mode.


What is the name of the software that would allow you to calculate the sums of numbers?

From what I see inside Expert Lotto, you’d have to calculate them one by one each game, without an additional software program that automates this calculation.

Regarding a registered user’s request for adding a min/max range value to the existing repeating numbers filter, I’d be happy to but first I’d like to know with the min/max ranges you type in: how come they would reduce a 13.9 million package (on the Demo 6/49 lotto) by such a large amount, by only using 3 levels as ranges?

Thanks


Hello....
This program I have is for personal use and you will not find it any place on the net.
Already the question of reduction so absurd, it concerns the use of the largest occurrences of any modality.
notice the biggest occurrences of your lottery.
It focuses on 0, 1 and 2, about 97.92%
The question of what to do in the EL, Just do it manually and write it down.
Much work.
The filter question, I have to try to explain it in another way, because until now no one here understood its operation.
In my other post, I put a brief explanation for it.

Take a look at it ... and see if you understand anything.
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Re: Unbelievable ... how to hit a jackpot.

Postby tdnl46w » Fri Jun 21, 2019 6:01 am

Hi D1Magnet.

D1Magnet wrote: ... From what I see inside Expert Lotto, you’d have to calculate them one by one each game, without an additional software program that automates this calculation. ...

For the EL 6/49 demo lotto(or any lotto), you can get repeating number count statistics for each draw by using a Complex Filter and the Performance feature. Insert a ticket file that has the current winning EL demo lotto tickets list into a empty EL package. Then setup a complex filter. In the design tab of the complex filter select 'Add filter' and select 'Repeating Numbers' from the list. Then setup the filter as follows;

Repeating Numbers
- Matching Tickets: [Accept]
- Winning Numbers:[1 latest draws - Wed 1st, Wed 2nd, Sun 1st, Sun 2nd]
- Min: [1] Max: [1]

Click on the Performance tab of the complex filter and select all 960 draws for both Tickets:(Package) and Draws:. Now go back in the complex filter Design tab, right click on the repeating numbers filter and select Performance. The performance results will show how many tickets each draw accepted(the stats we need), and you can also toggle the 'Accepted' column to see the lowest and highest values for that repeating numbers min:max(which was min:[1] max:[1]). This can be done for each min/max value as needed.

D1Magnet wrote: ... I’d like to know with the min/max ranges you type in: how come they would reduce a 13.9 million package (on the Demo 6/49 lotto) by such a large amount, by only using 3 levels as ranges? ...

The Match Winning Numbers filter and basically just filtering a filter result, and filtering that result(etc.) is how this can be achieved.
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