Unbelievable ... how to hit a jackpot.

Re: Unbelievable ... how to hit a jackpot.

Postby edymurph » Fri Jul 12, 2019 3:03 am

Hi D1magnet ...
Thank you again for always being available for these calculations.
I found it interesting to add (1.46 ... 1.47 ... 1.48, etc.) in the value of 1640.
But I wonder where you got it, or if it was just your normal calculations.
Too bad it's not a standard number.
Let's continue our studies, we're getting close.

Now I would like to ask you a particular question, I do not know if you will understand.

I'm using a certain type of filter in a packet of numbers where it contains a jackpot ...
I'm using min and max where it's within the margin.
ex. I have a min and max limit of 0 to 10.
So I use min and max 6 ... but for some reason this filter is discarding the jackpot ... is it because?
Something is wrong, or my program has a bug.
I already noticed this not only in 1 filter, but in 3 filters they are giving error.

Would you know why?
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Re: Unbelievable ... how to hit a jackpot.

Postby D1Magnet » Fri Jul 12, 2019 5:27 pm

Hi edymurph, with the addition to the 1640 number, I found it by trying to approximate the correct input number that would find the 866,362 answer. As the 1640, raised to the power of 2 * 0.32154395 was about 1500 out, so I experimented with the original starting figure & found these numbers.

I tried this idea further on the spreadsheet I attached by reversing the original equation of the power2 amount, back to the correct input number to give the answer. In excel =CELL^(1/2)

I calculated the 2 digit and 3 digit input numbers that find the answer. Now we could look at the number series, maybe try some pivot points on it & look for a pattern.

Question

I have a question about the original starting numbers of the answers, 865,276 & 866,362. Where did these original starting numbers come from as being the correct answer to the series?

As once you have this number you can easily add the correct 1086, 1076 etc series upon it. The reason I ask is later on I’d be interested in recreating this on the Demo 6/49 lotto to see if a similar pattern exists.


With the filter question:

Is this the Match Winning Numbers Filter in Expert Lotto, where the 3 filters are in a complex filter, being filtered down one by one to reduce the package to a low amount?

With the filtering that you’re doing discarding the jackpot ticket in your ticket package over the 3 filters, you might want to ask on your previous post Summation Filter, as it was about the filtering questions.

Thanks
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Re: Unbelievable ... how to hit a jackpot.

Postby edymurph » Fri Jul 12, 2019 7:06 pm

Hello D1 ...
Thanks for the spreadsheet ...
Now I understand your study perfectly.
Funny ... I was going to send you this reverse study sheet, just like I did earlier, just to see what the real value should be there to find the exact value.
Not as well made as yours, but you could understand.
I noticed that using two decimal places, is very close to the real value ...
Now with the three correct decimal places we have the 100% forecast.
The problem again .... (how to know which 3 correct values?)
We have to study where these numbers come from.

Regarding the question (I have a question about the initial numbers of the answers, 865,276 and 866,362.) Where did these original starting numbers come from as the correct answer for the series?)
These numbers are the sum total of each number (5,6,7,8,9,10,11,12,13,14,15)
Where we have there only the sum of (9) (865,276 in 1639 ... 866,362 in the 1640 ... 867,438 in the 1641 ... etc) See if you can understand.
My software shows this.

The filter question exclude the jackpot, then I make an image and put it in the other post.

Another topic.
Did you notice that the pivot number will always be the sum of the 3 numbers divided by 3?
Ex :(HIGH+LOW+CLOSE divided by 3)
452 + 228 + 276 = 956/3 = 318,666
A quick question.
We know that in the lottery that I play .. (lotofacil) when you repeat a number of numbers from the previous draw, you have a certain amount of games within your universe.
Example.
Never repeated the 15 numbers
The most common is to come 7,8,9 from the previous draw.
So, if you repeat 9 of the previous draw we have 1051050 games inside the universe like this parameter.
If you repeat 10 of the previous draw we have 756.756 games within the universe with this parameter.
etc...
Observe the figure ..
If you repeat 12 of the 15 we have 54,600 games with this parameter within your total universe.
Why do you have 2 filters in EL called (NUMBERS GROUPS)?
When I use what is in the tools tab with a draw that has repeated 12 numbers from the previous draw, does it only generate 15,015 games?
Sometimes with the 15 inside and sometimes not ... do you know why it only generates that amount?
Thank you
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Re: Unbelievable ... how to hit a jackpot.

Postby D1Magnet » Sat Jul 13, 2019 5:17 pm

Hi edymurph, this first post is regarding your filter question:

(from the help file) What are Number Groups?

Number groups divide all or selected pool numbers into several sub-pools or groups. Usually the whole number pool is divided into evenly sized groups and tickets are analyzed to see how many groups their numbers fall in. Ticket filter accepting tickets that have (not) numbers in selected groups is also available.
There are two types of number groups:
• Range groups - each group is a continuous range of numbers, e.g. 1-10, 11-20, 21-30 etc. The groups may also overlap and do not have to cover the whole number pool. So in a x/49 lottery you can define number groups like this: 1-10, 20-35, 30-49
• Discrete numbers groups - each group is a set of hand-picked numbers, e.g. 1-2-10-11-49, 3-4-5-6, 1-2-39-41-48-49. Note that a number can be included in more than one group.
You can define several named sets of number groups using Number Groups Manager. The number groups are then available in Number Groups filter and statistics.
-----------------------


(Your question) When I use what is in the tools tab with a draw that has repeated 12 numbers from the previous draw, does it only generate 15,015 games?
Sometimes with the 15 inside and sometimes not ... do you know why it only generates that amount?

No I don’t know why it generates that amount from within your results, but also I don’t know how you’ve set up your number groups.



From my installed version of E.L, inside the Numbers Group Filter, there is an option to use default number groups or customize my number groups. I selected customized groups each time.

(Firstly I inserted a full wheel of 3.2 million combinations (Package, Insert, Full Wheel))

My first thought was you’d be using discrete numbers (these are hand picked numbers in within a group), as you’re looking for repeating numbers over the whole 3.2 million package.

(I tried range groups (these are sets/groups of consecutive numbers) with all the 25 numbers in it’s number group, looking for min 12 & max 12, and it returns 0 each time)

• Discrete numbers groups - each group is a set of hand-picked numbers, e.g. 1-2-10-11-49, 3-4-5-6, 1-2-39-41-48-49. Note that a number can be included in more than one group.

If you’re filtering the whole package looking for Repeating Numbers, in discrete groups it let’s you specify the particular numbers you are looking for. I don’t know how this filter would be looking for repeating numbers, along each row in the ticket package though.

This filter is just checking the (25) specified numbers you’ve set in it’s group, against the whole package (from what I understand) and it’s looking for min 12 (numbers) and max 12 (numbers) along the rows, and at least 1 to 1 groups must pass (which is the one group only that has been ticked)

In discrete number groups, selecting all 25 numbers in it's group, looking for min 12 & max 12, and it returns 0 each time (as I think all 12 numbers out of the 25 group would be found all the time on each row??)

I don’t know how you’ve set up (what particular numbers are in) your number group with 1(ticked) and numbers in group min 12, max 12 (from your screenshot)

UPDATE

I tried the filter Match Winning Numbers, 1 latest draw, and only selected level 12, and it returned 54,600 tickets against the full ticket package. (see screenshots)

I believe this is what you’re looking for :D

(Useful tip) In the filter box you can press CTRL+A to highlight all the cells (blue colour), click in any column box to remove all the ticks at once. Then click into another empty cell (not the column cells) Now all cells are blank and you can tick just 12 only.

Hope this helps!
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Re: Unbelievable ... how to hit a jackpot.

Postby D1Magnet » Sat Jul 13, 2019 5:18 pm

last screenshot
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Re: Unbelievable ... how to hit a jackpot.

Postby D1Magnet » Sat Jul 13, 2019 5:33 pm

Hi edymurph

That’s interesting you were about to send me the same sheet! Yes we’ll study more on these numbers and hopefully find some pattern :D

Pivot Points

With the pivot point calculations, in the spreadsheet, if you look in the cells (especially F3) and see how the formulas are constructed, you’ll see the various calculations, and how the pivot is High + Low + Close divided by 3.

The cells in the spreadsheet show the Excel formulas, also the Baby Pips Pivot Point Calculator website shows all the mathematical formulas and how they’re calculated. (This is how I created this spreadsheet originally)

The initial answer numbers 865,276 and 866,362


I’ve tried some calculations to try and get the correct answer sums (860,000 ish number) each game.

On the spreadsheet I’ve attached

I know this is game 1821 data. (From what I understand) since the draw sum starts at 1, and by game 1639 the draw sum is 1639, if you sum all these draw sum numbers like I did over columns B&C (between games 1-1639), they become a 1.3 million number for games 1639-1650.

Then I tried to multiply this 1.3 mil number by the percentage number for draw 1639 (0.320927394) but the answers aren’t coming up with the correct red answer numbers, although the number is close to the red answer number.

Could you please explain how to calculate this number correctly, or what I’m doing wrong?

Thanks
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Re: Unbelievable ... how to hit a jackpot.

Postby edymurph » Sun Jul 14, 2019 4:25 pm

Hello D1.
Yes ... As I said at the beginning of this topic, these calculations can be used in any lottery (of course, each lottery will be different, but the concept is the same)
Also I think I showed you the sum for your lottery if I'm not mistaken.

You said ------- (What is the name of the software that would allow you to calculate the sums of numbers?
From what I see in the Expert Lotto, you would have to calculate them one by one with each game, without an additional software program that would automate that calculation.
Regarding a registered user's request to add a minimum / maximum range value to the existing repeating number filter, I'd be happy, but first I'd like to know with the minimum / maximum ranges you type: how would they reduce a 13.9 million packages (in the demo lottery 6/49) for such a large amount, using only 3 levels as ranges? )
----- The Tdnl46w resposndeu ...
(Hi tdnl46w, thanks a lot for your example and instructions on how to see these repeated numbers counting statistics inside the complex filter. I did as you said and saw the statistics of the result accepted on each withdrawal date, based on the min 1 level & max 1 for that particular example.Therefore, this could be repeated for the other levels to compile a data file.
With the filter winning game numbers, I now see in the other post, as it is being used to reduce each level one at a time to give the lowest final ticket count) ----
As I said ... I can not verify if the EL shows the sum of these numbers because I do not have the recorded version.

About the theme (865,276 ... 866,362 ... 867,438 ...)
I think I explained the concept of sum of numbers incorrectly (5,6,7,8,9,10,11,12,13,14,15)
I'll send you the spreadsheet that shows the sum of each number in each contest, so it may be better understood.
I have to do one by one, because with each contest these numbers change.
(I mean from 1639 to the 1640, it had 1640 amendments)
(from 1640 to 1641 it had 1641 alterations, and so on)
But I find it impossible to know which of these numbers will change.
See if you can understand and tell me.

I decided to split it into 4 parts so it fits here, then it's just joining it.
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Re: Unbelievable ... how to hit a jackpot.

Postby edymurph » Mon Jul 15, 2019 1:37 pm

the last part
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Re: Unbelievable ... how to hit a jackpot.

Postby edymurph » Tue Jul 16, 2019 12:06 am

When I say change, it means that.
When you look at the draw, (it can be anyone, 1639,1640,1641 ... etc) you will realize that the number 1 in position 9 has a certain number, the number 2 in position 9 another number, so to the current end)
When the 1640 draw took place, there were 543 changes within position 9 in varis numbers, just can not know before, what numbers will change.
Remember, I'm just talking about position 9, but the changes happen in (5,6,7,8,9,20,11,12,13, sometimes in the 14th and always comes 1 in the 15, which actually was the current draw)

I do not know if you will understand what I said, but check the file, if you have any questions, let me know.
Thank you..
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Re: Unbelievable ... how to hit a jackpot.

Postby D1Magnet » Tue Jul 16, 2019 3:44 pm

Hi edymurph

Thank you very much for posting the 4 files that have the sum of each number in each contest. :D

I can clearly see how this figure is calculated now & how this sum figure changes game to game (which are the answer numbers we've been working on finding a pattern for) And also how you explained in game 1640, position 9 had 543 alterations.

With the 543 alterations, you mean 543 alterations (or changes) down the position 9 column of data?

I've attached a spreadshseet on some pivot calculations on the decimal series (1.43, 1.46,1.48) This was based on what direction it would go (if you actually did know) From what I could see after going up for 3 or 4 moves, it went down 2, then up again. However this is only a sample of 10 numbers of data, which isn't many to test for a direction pattern.

Also once you'd chosen direction, the answer could vary on the 4 possible Floor Pivots used, that were large enough to accommodate the High- Low ranges.

Thanks
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Re: Unbelievable ... how to hit a jackpot.

Postby D1Magnet » Tue Jul 16, 2019 4:38 pm

Hi edymurph.

I can not verify if the EL shows the sum of these numbers because I do not have the recorded version.


Below are some screenshots and the data output from Expert Lotto's complex filter.

As you can see (for game 1640) the numbers in the column seem to be the same as on your spreadsheet for position 9, but E.L leaves the last draw off 1640 (eg latest answer = 543, (which is then found under the repeating numbers analyzer instead))

Also it doesn't show the sum of the column, but you can easily export to Excel for this. When I did this in Excel on the 2 exported files attached, it gave different numbers to your spreadsheet (eg 1086/2 =543). In E.L it was 866900 - 865819 = 1081 /2 = 540.5, which isn't a difference of 543.

So then I put the position 9 column from E.L against the data from your spreadsheet to check. All the figures were the same (except E.L leaves off the latest draw figure of 543) and both the columns sum was 865819 in Excel & if you add in the latest figure of 543, it equal 866,362 for game 1640.

Thanks
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Re: Unbelievable ... how to hit a jackpot.

Postby D1Magnet » Tue Jul 16, 2019 4:38 pm

last attachment
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Re: Unbelievable ... how to hit a jackpot.

Postby edymurph » Tue Jul 16, 2019 6:47 pm

Hi D1.
Thanks again.
When did you say

(It also does not show the column sum, but you can easily export to Excel for this.) When I did this in Excel in the two exported files attached, it gave different numbers to your worksheet (eg 1086/2 = 543). EL was 866900-865819 = 1081/2 = 540.5, which is not a difference of 543.
So, I put the EL position 9 column in your spreadsheet data to verify. All the figures were the same (except that EL leaves the last draw of 543) and both columns were 865819 in Excel and if you add the last number of 543, it equals 866,362 for the 1640 game.)

That's exactly it, your program shows only the sum of that number once, mine already shows it duplicated.
Ex.
My softaware (865,276 + 1086 = 866,362)
Your software
865,276 + 543 = 865,819)
But I guess that does not influence the time to find a pattern.

(Also does not show the column sum, but you can easily export to Excel for this.)
Yes ... I noticed that it does not show the sum of the numbers, only the average.
But as you said, you can take it to EXCEL and work with it and see the sums.

(With the 543 changes, do you mean 543 alteration (or changes) in position 9 of the data column?)
I am referring to alteration in position 9, but it happens in all columns, but as we are talking about position 9, I will send you a spreadsheet to see this alteration.
Thank you.
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Re: Unbelievable ... how to hit a jackpot.

Postby edymurph » Tue Jul 16, 2019 7:37 pm

I think it would be interesting to try to find the value for the 3 decimal places.
Notice that...

2691004,023
2694381,083
2697727,411
2701036,371
2704488,788
2707555,066
2710744,916
2714068,438
2717413,778
2720771,075
2724057,823
2727260,679
Up to the 3rd house, there is a change every 3 contests.
Until the 4th house almost had a standard, 1,4,7 ... 1,4,7 ... 0,4,7 ... 0,4,7 ...
From then on, you can not predict.

Note also that within 12 contest the variation was between (1.40 ... 1.50) and
stayed out only 1.533.
1.428
1,457
1,476
1,483
1,533
1.465
1,434
1,443
1,458
1,476
1,472
1.442
I would like to analyze if this is the variation that exists in each contest ... from (1 to the current 1840)
For this I will have to see the sum of each of these numbers ...
This will be a lot of work, because my software only shows the sum of a single result.
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Re: Unbelievable ... how to hit a jackpot.

Postby edymurph » Tue Jul 16, 2019 9:36 pm

I just did it here ... it's not like yours, but it works.
Thank you
:lol: :lol: :lol: :P :P :P
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