Pushing Numbers To Top Occurrences

Pushing Numbers To Top Occurrences

Postby Joe » Thu Jan 15, 2009 6:02 am

Friends, I tried Simulation back test in my lotto game watching the Top occurrences of the winning numbers, I was expecting four numbers within top 10 occurrences so that i can get the money back, but I didnt find such a possibility there, I am getting four numbers above 20 Tops only,

Is there any other way to push these numbers to the Top Occurrences?, your help will be valuable to me and all thanks,
Joe
 
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Postby sysp34 » Thu Jan 15, 2009 6:29 am

Joe

i guess using top 10 hard to get 4 of 6 mostly 2 of 6 or little bit often 3 of 6

i've been using most occurrence using last 360 draws with "adjacent" or cross section WNH in spreadsheet but mostly one or two trapped in repeating positional using top occurrence

well since you've
I am getting four numbers above 20 Tops only


why not creating "conditional"
top 10 mostly 2/3 of 6
top 11-20 mostly 2/3 of 6

then substitute top 10 and top 11-20 although it sound easy but i guess it will failed when comes to get the money back :motz: :#: :wand:

gl :gun:
sysp34
 
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Postby Joe » Thu Jan 15, 2009 6:35 am

[quote=sysp34]
why not creating "conditional"
top 10 mostly 2/3 of 6
top 11-20 mostly 2/3 of 6

then substitute top 10 and top 11-20 although it sound easy but i guess it will failed when comes to get the money back :motz: :#: :wand:[/quote] thanks sys, even tried these settings too and tested on my results, its too hard to get money back as you said, I am expecting some more cool filters to push numbers to top, thanks
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Postby Jerzy » Fri Jan 16, 2009 6:34 am

Joe,

Did you try to use the History Differences filter on the basis of occurrences of the last draw numbers in the 1st row of columns?

To use this filter this way:

- enter the last draw result into the Winning Numbers data base
- open the History Differences page and mark the last draw numbers in rows by entering them into checkboxes

In column 0, there will be 6 numbers in the 1st row, all of them marked. In the remaining columns, most likely, there will be from 0 to 2 numbers. 3 numbers from the last draw in a row is a possibility, but it doesn't happen often.

Open the History Differences filter and enter the following settings:

Number count: 0 to 6
History differences: 1 to 1
Numbers in a single column: 0 to 2
Even numbers: 0 to 6
Columns to use: select only the column 0

Click Leave, click OK or Apply.

If you use the filter this way, it will work as a kind of repeats filter. The tickets with 0, 1, and 2 numbers repeated from the last draw will be left in the package, and the tickets with 3, 4, 5, and 6 repeated numbers will be removed.

Use the same basic settings, but select a different column, and filter the 1st row in that column. Do it for all columns. The filtering could be very effective, but I am not sure whether it pushes the numbers to the top occurrence.

You can target also other rows in columns if they contain the last draw winning numbers, and you can try also different settings and filter several columns at a time.

Good luck!
Jerzy
 
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Postby Joe » Fri Jan 16, 2009 12:51 pm

thanks jery, let me try this
Joe
 
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Postby Joe » Fri Jan 16, 2009 4:02 pm

i think we need more enhancements in calculating simulation in order to push the winning numbers to top occurrences, your ideas are welcome and will be helpful to make this feature more efficient, thanks
Joe
 
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Postby sysp34 » Tue Jan 20, 2009 1:07 pm

Joe , Stan and JACKPOT members

how about this one, this is only a hypothetical.

first we knew in Pick 6 can be split into pick 3 using last digit or origin pick 6 number
(i use pick 3 last digit since i had the number groups)

A = 123xxx + xxx456
B = 12x4xx + xx3x56
C = 12xx5x + xx34x6
D = 12xxx6 + xx345x
E = 1x34xx + x2xx56
F = 1x3x5x + x2x4x6
G = 1x3xx6 + x2x45x
H = 1xx45x + x23xx6
I = 1xx4x6 + x23x5x
J = 1xxx56 + x234xx

from above step we create grouping numbers (2,3,4,5) and split into pair since
we like to find 10 numbers then we might use 4G or 5G (5 group)
[m]
4G (3x3x2x2)
1 = 3 numbers (eg: 012)
2 = 3 numbers (eg: 345)
3 = 2 numbers (eg: 67)
4 = 2 numbers (eg: 89)

possible 4 group combination : 210
using unique short pick 4 numbers as an anchor, we have 210 patterns (combin(10,4))

pairs
11 = (9 pr) = [eg: 012 x 012]
12 = (9 pr) = [eg: 012 x 345]
13 = (6 pr) = [eg: 012 x 67]
14 = (6 pr) = [eg: 012 x 89]
21 = (9 pr) = [eg: 345 x 012]
22 = (9 pr) = [eg: 345 x 345]
23 = (6 pr) = [eg: 345 x 67]
24 = (6 pr) = [eg: 345 x 89]
31 = (6 pr) = [eg: 67 x 012]
32 = (6 pr) = [eg: 67 x 345]
33 = (4 pr) = [eg: 67 x 67]
34 = (4 pr) = [eg: 67 x 89]
41 = (6 pr) = [eg: 89 x 012]
42 = (6 pr) = [eg: 89 x 345]
43 = (4 pr) = [eg: 89 x 67]
44 = (4 pr) = [eg: 89 x 89]

pair sum

2 (9 pr) => 11 = [eg: 012 x 012]
3 (18 pr) => 12 = [eg: 012 x 345]
21 = [eg: 345 x 012]
4 (21 pr) => 13 = [eg: 012 x 67]
22 = [eg: 345 x 345]
31 = [eg: 67 x 012]
5 (24 pr) => 14 = [eg: 012 x 89]
23 = [eg: 345 x 67]
32 = [eg: 67 x 345]
41 = [eg: 89 x 012]
6 (14 pr) => 24 = [eg: 345 x 89]
33 = [eg: 67 x 67]
42 = [eg: 89 x 345]
7 (8 pr) => 34 = [eg: 67 x 89]
43 = [eg: 89 x 67]
8 (4 pr) => 44 = [eg: 89 x 89]


distance pair
0 (24 pr) => 11 = [eg: 012 x 012]
22 = [eg: 345 x 345]
33 = [eg: 67 x 67]
44 = [eg: 89 x 89]
1 (38 pr) => 12 = [eg: 012 x 345]
21 = [eg: 345 x 012]
23 = [eg: 345 x 67]
32 = [eg: 67 x 345]
34 = [eg: 67 x 89]
43 = [eg: 89 x 67]
2 (24 pr) => 13 = [eg: 012 x 67]
31 = [eg: 67 x 012]
24 = [eg: 345 x 89]
42 = [eg: 89 x 345]
3 (12 pr) => 14 = [eg: 012 x 89]
41 = [eg: 89 x 012]

5G (2x2x2x2x2)
1 = 2 numbers (eg: 01)
2 = 2 numbers (eg: 23)
3 = 2 numbers (eg: 45)
4 = 2 numbers (eg: 67)
5 = 2 numbers (eg: 89)

possible 5 group combination : 945

pair sum each groups contain 4 pair
2 => 11 = [eg: 01 x 01]
3 => 12 = [eg: 01 x 23]
21 = [eg: 23 x 01]
4 => 13 = [eg: 01 x 45]
22 = [eg: 23 x 23]
31 = [eg: 45 x 01]
5 => 14 = [eg: 01 x 67]
23 = [eg: 23 x 45]
32 = [eg: 45 x 23]
41 = [eg: 67 x 01]
6 => 15 = [eg: 01 x 89]
24 = [eg: 23 x 67]
33 = [eg: 45 x 45]
42 = [eg: 67 x 23]
51 = [eg: 89 x 01]
7 => 25 = [eg: 23 x 89]
34 = [eg: 45 x 67]
43 = [eg: 67 x 45]
52 = [eg: 89 x 23]
8 => 35 = [eg: 45 x 89]
44 = [eg: 67 x 67]
53 = [eg: 89 x 45]
9 => 45 = [eg: 67 x 89]
54 = [eg: 89 x 67]
10 => 55 = [eg: 89 x 89]

distance pair
0 (20 pr) => 11 = [eg: 01 x 01]
22 = [eg: 23 x 23]
33 = [eg: 45 x 45]
44 = [eg: 67 x 67]
55 = [eg: 89 x 89]
1 (32 pr) => 12 = [eg: 01 x 23]
21 = [eg: 23 x 01]
23 = [eg: 23 x 45]
32 = [eg: 45 x 23]
34 = [eg: 45 x 67]
43 = [eg: 67 x 45]
45 = [eg: 67 x 89]
54 = [eg: 89 x 67]
2 (24 pr) => 13 = [eg: 01 x 45]
31 = [eg: 45 x 01]
24 = [eg: 23 x 67]
42 = [eg: 67 x 23]
35 = [eg: 45 x 89]
53 = [eg: 89 x 45]
3 (16 pr) => 14 = [eg: 01 x 67]
41 = [eg: 67 x 01]
52 = [eg: 89 x 23]
25 = [eg: 23 x 89]
4 ( 8 pr) => 15 = [eg: 01 x 89]
51 = [eg: 89 x 01]
[/m]

then start tracking a "due" pair from 4G or 5G for JACKPOT format A,B,C,D,E,F,G,H,I,J and we might have pair intersection.

then calculate the pairs occurrence and skip and use it as pair key numbers.

i though using this we might have at least 2 of 6 and sometimes 4 of 6, and just lucky we might have JACKPOT.

well i dunno if this will work and since it take hugh algorithm creating those code, also this is just hypothetical using pick 3 number groups

good luck :gun :gun :gun:
sysp34
 
Posts: 559
Joined: Thu Nov 30, 2006 2:22 am

Postby lottoboy » Wed Jan 21, 2009 3:28 am

[quote=Jerzy:1232080466]
Joe,

Did you try to use the History Differences filter on the basis of occurrences of the last draw numbers in the 1st row of columns?

To use this filter this way:

- enter the last draw result into the Winning Numbers data base
- open the History Differences page and mark the last draw numbers in rows by entering them into checkboxes

In column 0, there will be 6 numbers in the 1st row, all of them marked. In the remaining columns, most likely, there will be from 0 to 2 numbers. 3 numbers from the last draw in a row is a possibility, but it doesn't happen often.

Open the History Differences filter and enter the following settings:

Number count: 0 to 6
History differences: 1 to 1
Numbers in a single column: 0 to 2
Even numbers: 0 to 6
Columns to use: select only the column 0

Click Leave, click OK or Apply.

If you use the filter this way, it will work as a kind of repeats filter. The tickets with 0, 1, and 2 numbers repeated from the last draw will be left in the package, and the tickets with 3, 4, 5, and 6 repeated numbers will be removed.

Use the same basic settings, but select a different column, and filter the 1st row in that column. Do it for all columns. The filtering could be very effective, but I am not sure whether it pushes the numbers to the top occurrence.

You can target also other rows in columns if they contain the last draw winning numbers, and you can try also different settings and filter several columns at a time.

Good luck!
[/quote]

Jerzy:

I have tried your strategy for my Pick-6 but the final result is not good!
It still left 4184362 tickets and no JP. Also, the 2nd price just left 62!!
lottoboy
 
Posts: 738
Joined: Sat Dec 08, 2007 8:37 pm

Postby lottoboy » Wed Jan 21, 2009 3:54 am

[quote=Joe:1231992137]
Friends, I tried Simulation back test in my lotto game watching the Top occurrences of the winning numbers, I was expecting four numbers within top 10 occurrences so that i can get the money back, but I didnt find such a possibility there, I am getting four numbers above 20 Tops only,

Is there any other way to push these numbers to the Top Occurrences?, your help will be valuable to me and all thanks,
[/quote]

Hi, Joe:

I'm very interesting your new idea which pushing the winning numbers to top occurrences. In fact, I was trying for it by using Stan's strategy(sorted statistics) but it's really not working. Could you tell me the details how can you use the Simulation back test to find the Top occurrences? I want to try it too. Thanks.

Best,
lb
lottoboy
 
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Postby Jerzy » Wed Jan 21, 2009 4:28 pm

lottoboy,

I do not know why you lost the JP ticket. Maybe in your game for this particular draw there were 3 winning numbers in a row in one or more columns. Or maybe you tested this filter for the last known draw but forgot to skip the last result in the data base. In my recommendations in the previous post I refered to the situation when you just prepare the tickets for the next draw and in this situation the last draw result should not be skipped.

However, when you are testing the History Differences filter on the basis of the last known drawing result, you have to skip the last result.

The best results with History Differences filter can be achieved if you work with single rows in single columns. There are 11 columns and even more rows in each column - a lot of work to do, but results coold be good. And a fast computer is necessary to do it quickly.

After skipping the last draw, open the History Differences page and see how many rows there are in each column, how many winning numbers in each row. Notice that in the 3rd segment there are predominantly short rows, with 1 or 2 numbers and many of them contain no winning numbers. For them the Numbers in a single column parameter could be 0 to 1 or 0 to 0, instead od 0 to 2. Unfortunately, the filter doesn't allow for 0 to 0.

Number count: 0 to 6, because theoretically there could be 0 to 6 winning numbers in a row.
Numbers in a single column 0 to 2 because practically there are 0 to 2 winning numbers in a row. 3 winning numbers in a row in my game are rare, but can occur sometimes. See how it is in your game.
Even numbers 0 to 6, because from 0 to 6 winning numbers in the row can be even numbers.
And History differences parameter is the row number in the History Differences tab.

Each row in each column can be filtered, some rows with Numbers in a single columns 0 to 2 and some rows with 0 to 1. A significant package reduction is possible, but it is necessary to use other filters as well to make it small and manageable. I did not analyse how this method can push the winning numbers up in the occurrences stats. Probably it can be done if you enter parameters close to true values for Numbers in a single column.

Good luck!
Jerzy
 
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Joined: Mon Sep 18, 2006 5:26 am

Postby Jerzy » Wed Jan 21, 2009 4:51 pm

Stan,

I believe that it would be very useful if you changed the lowest possible value of Numbers in a single column in the History Differences filter from 0 to 1 to 0 to 0. There are rows in columns with no winning numbers, and the best results with the History Differences filter can be achieved when each row in each column is filtered separately.

Could you do this for EL version 5 and for current version as well?
Jerzy
 
Posts: 811
Joined: Mon Sep 18, 2006 5:26 am

Postby lottoboy » Wed Jan 21, 2009 10:34 pm

[quote=Jerzy]
lottoboy,

I do not know why you lost the JP ticket. Maybe in your game for this particular draw there were 3 winning numbers in a row in one or more columns. Or maybe you tested this filter for the last known draw but forgot to skip the last result in the data base. In my recommendations in the previous post I refered to the situation when you just prepare the tickets for the next draw and in this situation the last draw result should not be skipped.

However, when you are testing the History Differences filter on the basis of the last known drawing result, you have to skip the last result.

The best results with History Differences filter can be achieved if you work with single rows in single columns. There are 11 columns and even more rows in each column - a lot of work to do, but results coold be good. And a fast computer is necessary to do it quickly.

After skipping the last draw, open the History Differences page and see how many rows there are in each column, how many winning numbers in each row. Notice that in the 3rd segment there are predominantly short rows, with 1 or 2 numbers and many of them contain no winning numbers. For them the Numbers in a single column parameter could be 0 to 1 or 0 to 0, instead od 0 to 2. Unfortunately, the filter doesn't allow for 0 to 0.

Number count: 0 to 6, because theoretically there could be 0 to 6 winning numbers in a row.
Numbers in a single column 0 to 2 because practically there are 0 to 2 winning numbers in a row. 3 winning numbers in a row in my game are rare, but can occur sometimes. See how it is in your game.
Even numbers 0 to 6, because from 0 to 6 winning numbers in the row can be even numbers.
And History differences parameter is the row number in the History Differences tab.

Each row in each column can be filtered, some rows with Numbers in a single columns 0 to 2 and some rows with 0 to 1. A significant package reduction is possible, but it is necessary to use other filters as well to make it small and manageable. I did not analyse how this method can push the winning numbers up in the occurrences stats. Probably it can be done if you enter parameters close to true values for Numbers in a single column.

Good luck!
[/quote]

Jerzy,

Thanks for your reply! The below is my test by using your strategy:

1) My Pick-6: CT 6/44
2) The full tickets: 7059052
3) The history data: 1128 tickets (from 03/13/98 to 01/16/09)
4) I have skipped the data of 01/16/09 (05-11-20-28-43-44) as the next draw, or my predicting data and the last drawing ticket is 01/13/09 (02-04-16-22-30-40);
5) The setting in the filter of HD:
Number count: 0 to 6
History differences: 1 to 1
Numbers in a single column: 0 to 2
Even numbers: 0 to 6
And the same settings for all 11 columns;
6) The final result is as below:
0: 179494 tickets out; 1/228 (JP/2nd prize)
-1: 814324 out; 1/196
-2: 146462 out; 1/196
-3: 452343 out; 0/84 (Note: the JP lost in the column)
-4; 546154 out;
-5; 384864 out;
-6; 328282 out;
-7; 2835 out;
-8; 19932 out;
-9; 0 out;
-10; 0 out;
Finally, 4184362 tickets still left in the package and 0/62.

Any mistake above please let me know, thanks.

In addition, how many tickets left and how about your winning status (JP/2nd prize) in your back tests by using your strategy generally?

good luck,
lb
lottoboy
 
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Postby Jerzy » Thu Jan 22, 2009 2:34 am

lottoboy,

You skipped the right drawing in the data base and you filtered all columns but only the 1st row in each column. The jackpot ticket was lost while filtering the 1st row in the column -3.

Could you check how many winning numbers (05-11-20-28-43-44) are present in the 1st row of the column -3, when the last visible result in the Winning Numbers data base is that of 01/13/09 (02-04-16-22-30-40) ?

When the last draw visible in the Winning Numbers is that of 01/13/09, open the History Differences tab in WN History, click on Update button. To mark the winning numbers 05-11-20-28-43-44 in the tab, enter these numbers into the Draw Simulation boxes in the tab, but don't click on Draw Simulation button. Open the column -3 in the HD tab and see how many of these winning numbers are present in the 1st row of this column. If there are more than 2 winning numbers, it will be the cause of losing the JP ticket with the setting of Numbers in a single row 0 to 2. If there are 3 winning numbers this setting should be 0 to 3 or even 3 to 3 which would be more specific, more effective but more difficult to predict.

In a similar way, analyse all columns in at least the last 10 drawings, to see what is typical count of winning numbers in a row. See how often occur more than 2 numbers in a row. Compare what happens in the 1st, 2nd and 3rd segment. You will notice that in the 3rd segment the rows tend to be short (1-2 numbers in a row). These rows can be filtered as well, but obviously the setting Numbers in a single row should be 0 to 1.

The other cause of losing the JP ticket, or actually overlooking it, could be a wrong method of identifying the JP ticket.

To analyse the package after filtering, you should use the Win Test and enter the result 05-11-20-28-43-44 into the boxes.
Jerzy
 
Posts: 811
Joined: Mon Sep 18, 2006 5:26 am

Postby lottoboy » Thu Jan 22, 2009 4:20 am

[quote=Jerzy]
lottoboy,

You skipped the right drawing in the data base and you filtered all columns but only the 1st row in each column. The jackpot ticket was lost while filtering the 1st row in the column -3.

Could you check how many winning numbers (05-11-20-28-43-44) are present in the 1st row of the column -3, when the last visible result in the Winning Numbers data base is that of 01/13/09 (02-04-16-22-30-40) ?

When the last draw visible in the Winning Numbers is that of 01/13/09, open the History Differences tab in WN History, click on Update button. To mark the winning numbers 05-11-20-28-43-44 in the tab, enter these numbers into the Draw Simulation boxes in the tab, but don't click on Draw Simulation button. Open the column -3 in the HD tab and see how many of these winning numbers are present in the 1st row of this column. If there are more than 2 winning numbers, it will be the cause of losing the JP ticket with the setting of Numbers in a single row 0 to 2. If there are 3 winning numbers this setting should be 0 to 3 or even 3 to 3 which would be more specific, more effective but more difficult to predict.

In a similar way, analyse all columns in at least the last 10 drawings, to see what is typical count of winning numbers in a row. See how often occur more than 2 numbers in a row. Compare what happens in the 1st, 2nd and 3rd segment. You will notice that in the 3rd segment the rows tend to be short (1-2 numbers in a row). These rows can be filtered as well, but obviously the setting Numbers in a single row should be 0 to 1.

The other cause of losing the JP ticket, or actually overlooking it, could be a wrong method of identifying the JP ticket.

To analyse the package after filtering, you should use the Win Test and enter the result 05-11-20-28-43-44 into the boxes.
[/quote]

Jerzy,

You are right!
05-10-15-18-20-31-34-42-44,9 numbers are present in the 1st row of the column -3, when the last visible result in the Winning Numbers data base is that of 01/13/09 (02-04-16-22-30-40).
And 3 numbers: 05-20-44 are the winning #s (05-11-20-28-43-44).
This is the reason of losing the JP with the setting of 0 to 2 really!

The below is my new result of test by changing the setting of Numbers in a single row:

0; (0-1) 1286719 out; 1/228
-1; (2-2) 4111793 out; 1/136
-2; (1-1) 963090 out; 1/96
-3; (3-3) 608982 out; 1/35
-4; (2-2) 74793 out; 1/13
-5; (0-1) 2556 out; 1/13
-6; (2-2) 6278 out; 1/11
-7; (0-1) 966 out; 1/11
-8; (0-1) 92 out; 1/11
-9; (1-1) 2524 out; 1/10
-10; (0-1) 0 out; 1/10

Finally, 1256 tickets left in the package and the prize is 1/10!!!
I believe firmly that the result should be much better if we can change the setting from (0-1) to (0-0) for Col.0, -5, -7, -8, and -10.
It's real good strategy!!

In deed, we can not predict the setting of Numbers in a single row correctly for each Col. but we can do it as well as possible based on the statistics to history data. I think Jerzy's strategy is very simple but more
effective than some methods. Thanks Jerzy!!!

Best regards,
lottoboy
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Postby Jerzy » Thu Jan 22, 2009 5:45 am

lottoboy,

I am glad that you found the reason for losing the JP ticket and that you know how to use the HD filter.

But you should try to filter all possible rows in all columns. However, I need to say that the rows with 1 or 2 numbers in them (any numbers, not necessarily winning numbers) cannot be filtered with Numbers in a row setting 0 to 2. It doesn't make sense and it will not result in removing any combinations from the package. And the rows with 1 number in them cannot be filtered at all with this filter if you use Leave setting. You cannot enter Number in a column 0 to 0. The filter doesn't allow for that. I hope that Stan will remove this limitation. However, it is probably possible to filter one number rows with Remove, Numbers in a single column 1 to 1. This should remove single numbers from the column. Some combinations with these numbers would be removed from the package, but not all combinations with these numbers.

This is one of the best EL filters. Of course, like with other filters, we are running a risk of losing the JP ticket if we enter incorrect settings, but some tickets with lower prizes should remain in the package.
Jerzy
 
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