by maroc » Thu Aug 31, 2006 10:30 pm
Hi Stan,
I Will Try to explain as much as i could...
In lotto 6/49 we have a total of 13 983 816 combo each one is formed with 6 numbers.So we have 13.983.816 * 6 = 83.902.896 numbers.
To have all the above each number must appear 1.712.304 times.
With a % of 83.902.896 / 1.712.304 = 0.20408 for each number to appear in equal world of probability...
Let assume we have a 314 draws (=total sum of occurence column devided by 6) and the occurence of number 1 is 30 times.
Normaly all numbers must have an occurence value of :
314 draw * 6 numbers * 0.20408 = 38 times.
we have number 1 just with occurence of 30 times in 314 draws and in equal world we should have number 1 appeare 38 times so we consider number 1 as below normal frequency...
see attacheed file lotomIn General
Apply the same calc for numbers in ticket position and in all the others tables..
see attach file lotomin position 2
This freq value will help user to see if the numbers are equal , below or above the normal frequency (in equal world of probability) and help to make decision when to use the rank value.
For exemp if the number rank value is 100 and it's frequency is(very very ) below normal we will not take this number in our play...
hope i have been clear.
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