I'm opening this topic for lottery lovers and for those who like calculations.

In my recent studies, I have found that is it possible to find a pattern in these calculations, I can turn it into an application for any lottery mode.

I'll leave it here for those scholars and onlookers who want to try to find a pattern in these calculations.

If it has any pattern, the jackpot is in the hand, but if you find the calculations by approximation also works.

The only answers to (Position E) are available to see if all are on the right track, because here what matters is how to assemble the equation to reach these values.

LET'S SUPPORT THE FOLLOWING SCENARIO, WHERE WE HAVE 1640 ORANGES AND WILL DIVIDE THEM IN 11 PARTS, WHERE EACH POSITION WILL RECEIVE A VALUE ACCORDING TO ITS SPECIFICATION.

A (POSITION E) ALREADY HAS 865.276 ORANGES AND WE WANT TO KNOW WITH HOW MANY ORANGES IT WILL BE AT THE END OF THAT DIVISION.

(1) POSITION A = YOU CAN ONLY RECEIVE FROM (0-18) RECEIVED = 6

(2) POSITION B = YOU CAN ONLY RECEIVE FROM (22-82) RECEIVED = 46

(3) POSITION C = YOU CAN ONLY RECEIVE FROM (218-366) RECEIVED = 302

(4) POSITION D = YOU CAN ONLY RECEIVE FROM (672-892) RECEIVED = 782

(5) POSITION E = YOU CAN ONLY RECEIVE FROM (952-1176) RECEIVED = 1052

(6) POSITION F = YOU CAN ONLY RECEIVE FROM (644-880) RECEIVED = 744

(7) POSITION G = YOU CAN ONLY RECEIVE FROM (216-366) RECEIVED = 268

(8) POSITION H = YOU CAN ONLY RECEIVE FROM (24-94) RECEIVED = 70

(9) POSITION I = YOU CAN ONLY RECEIVE FROM (0-20) RECEIVED = 4

(10) POSITION J = YOU CAN ONLY RECEIVE FROM (0-4) RECEIVED = 2

(11) POSITION K = YOU CAN ONLY RECEIVE 2 AND ALWAYS RECEIVE = 2

SUM OF ALL NUMBERS = 3278

THEN WE WILL DIVIDIREMOS THE 1641 AND ALSO THE 1642 .... AND SO DURING UNTIL 1650.

HOW MANY ORANGES TO (POSITION E) WILL YOU RECEIVE AT THE END OF EACH DIVISION?

POSITION A 3,003= 0,091870%

POSITION B 50,050= 1,531162%

POSITION C 289,575= 8,858864%

POSITION D 772,200= 23,623637%

POSITION E 1,051,050=32,154,395%

POSITION F 756,756= 23,151164%

POSITION G 286,650= 8,769380%

POSITION H 54,600= 1,670358%

POSITION I 4,725= 0,144550%

POSITION J 150= 0,004589%

POSITION K 1= 0,000031%

TOTAL 3.268.760

(ANSWERS ONLY FOR POSITION E)

1640 = 866.362 (1086)

1641 = 867,438 (1076)

1642 = 868,502 (1064)

1643 = 869,612 (1110)

1644 = 870,598 (986)

1645 = 871,624 (1026)

1646 = 872,692 (1068)

1647 = 873,768 (1078)

1648 = 874,848 (1080)

1649 = 875,904 (1056)

1650 = 876,934 (1030)

What should be done here is as follows.

We have to make calculations to see how we get to these values (866.362 .... 867.438 .... 868.502) and so on.

Note that the first 3 digits go up one by one, the problem is the final 3.

Let's suppose...

Taking the number 1640 and raising it to the square, it will be (2,689,600) multiplied by 32,154395% we obtain the value of

864,824 .... well near the value 866.362.

A difference of 1538.

I still do not know how to get the correct value, but I want to get closer, because this difference of 1538 is still great.

You do not need to find the values for each number (5,6,7,8,9,10,11 13,13 14) because I only need one, and then I make that into something that I can apply in any lottery mode.