by PadawanLotto » Sat Mar 23, 2013 2:16 pm
The numbers were 5, 6, 7, 9, 19. I only had the 19 but I have learned a lesson here. I had last digit positions 3 and 4 correct but, based on the fact that I had the wrong last digits in positions 1 and 2 it caused the first digits to be incorrect in positions 3 and 4.
This is what I had played, P1=3 / P2=2, 3, 8, 9 / P3=3, 4, 5, 7 / P4=4, 5, 9 / P5=1, 2, 3, 7
How one positional last digit effects the next position is difficult to learn and I will have to study it some more.
By choosing 3 in P1 started me out with full numbers of 3, 13, 23.
By choosing 2 and 3 in P2 left me with the only possible full numbers of 12, 22, 32, 13, 23, 33. Now because the last digits 8 and 9 in P2 are higher than 3 in P1 this gives more full number range 8, 18, 28, 9, 19, 29.
Choosing certain last digits positional can wreck havoc on the other full numbers in other positions but, so can having the correct last digits in the correct positions but losing the match combinations trying to filter down the amount of combinations to an affordable amount.